p.284

　　   instants  together  to achieve a duration;  no matter
　　   how many such instants  are added together, their sum
　　   will always be zero.
　　　　  The  paradox  of the Stadium  is for  the  modern
　　   reader  the  most  baffling  of  the  four,  and  our
　　   interpretation,   which　　 follows,   differs　　 from
　　   Brumbaugh's.  We agree  with  him, however, that this
　　   puzzle   assumes   both   space   and   time   to  be
　　   discrete--composed of minims.

　　   The fourth argument  is that concerning  the two rows
　　   of bodies, each row being composed of an equal number
　　   of bodies  of equal  size, passing  each  other  on a
　　   race-course  as they proceed  with equal velocity  in
　　   opposite directions, the one row originally occupying
　　   the space between  the goal and the middle  point  of
　　   the  course  and the other  that  between  the middle
　　   point   and  the  starting-post.   This,  he  thinks,
　　   involves  the conclusion  that  half a given  time is
　　   equal to double that time.(7)

　　   Assume  for the moment  that we are speaking, as Zeno
　　   originally  did,  of  bodies  rather  than  chariots,
　　   Assume  a  stationary  body  (A) divided  into  three
　　   sections, each section  being one minim long.  Assume
　　   two more such bodies, one (B) traveling past (A) from
　　   left to right  at a certain  velocity, the other  (C)
　　   traveling  past (A) in the opposite direction  at the
　　   same speed.

　　   Let (B) be passing (A) at a velocity  of one minim of
　　   space  per  minim  of time.  Then  in the  time  (one
　　   temporal minim) in which the front edge of (B) passes
　　   one minim of (A), the front edge of (C) will pass two
　　   minims  of (B), and in doing so the front edge of (C)
　　   will pass one minim  of (B) in half a minim  of time,
　　   which is impossible, since the minim is by definition
　　   indivisible.
　　　　  This puzzle  would work just as well looked at in
　　   another  way.  If we say that the second moving  body
　　   (B) is passing the first (A) at the slowest  possible
　　   speed, that is, one minim of space per minim of time,
　　   then in the same duration  in which the front edge of
　　   (B) passes  one minim  of (C), it (B) will  pass only
　　   half a minim  of (A), the stationary  body, which  is
　　   impossible,   since,  once   again,  the   minim   is